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我是最近才开始学linux的,这有道题目 1、编写程序:用fork( )创建两个子进程,再用系统调用signal( )让父进程捕捉键盘上来的中断信号(即按^c键);捕捉到中断信号后,父进程用系统调用kill( )向两个子进程发出信号,子进程捕捉到信号后分别输出下列信息后终止:
Child process1 is killed by parent!
Child process2 is killed by parent!
父进程等待两个子进程终止后,输出如下的信息后终止:
Parent process is killed!
#include <stdio.h>
#include <signal.h>
#include <unistd.h>
void waiting( ),stop( );
int wait_mark;
main( )
{
int p1,p2,stdout;
while((p1=fork( ))= =-1); /*创建子进程p1*/
if (p1>0)
{
while((p2=fork( ))= =-1); /*创建子进程p2*/
if(p2>0)
{
wait_mark=1;
signal(SIGINT,stop); /*接收到^c信号,转stop*/
waiting( );
kill(p1,16); /*向p1发软中断信号16*/
kill(p2,17); /*向p2发软中断信号17*/
wait(0); /*同步*/
wait(0);
printf("Parent process is killed!\n");
exit(0);
}
else
{
wait_mark=1;
signal(17,stop); /*接收到软中断信号17,转stop*/
waiting( );
lockf(stdout,1,0);
printf("Child process 2 is killed by parent!\n");
lockf(stdout,0,0);
exit(0);
}
}
else
{
wait_mark=1;
signal(16,stop); /*接收到软中断信号16,转stop*/
waiting( );
lockf(stdout,1,0);
printf("Child process 1 is killed by parent!\n");
lockf(stdout,0,0);
exit(0);
}
}
void waiting( )
{
while(wait_mark!=0);
}
void stop( )
{
wait_mark=0;
}
运行结果
屏幕上无反应,按下^C后,显示 Parent process is killed!
为何预期的结果并未显示出?
程序该如何修改才能得到正确结果?
不修改程序如何得到期望的输出?
请各位帮忙看看,先谢谢啦 |
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