如何在c中实现对命令行程序的调用？？？

fazi

偶想实现调用命令行程序，调用时能传递参数，，
可以控制调用de程序，比如中止运行。。
望有经验的仁兄指点一二，
如果有详细的例程，那再好不过了：D

tingxx

system("command")不行吗？？

fazi

[quote:11ce359004="tingxx"]system("command")不行吗？？[/quote]
请问这位老兄能否指点一下就具体如何用？？
偶目前有点菜~~
或偶需要查那方面的资料呀？

mozilla

还不明白?
调用system("ls");试试

zzh2004linux

简单的说，这个东西可以放在任何地方，说的再简单点，直接调用，不用声明什么!

flyaway

用execl族也可以
不过要在过程中终止，你只能找到它的进程号kill就行了

flyaway

[code:1]
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
/* Spawn a child process running a new program. PROGRAM is the name
of the program to run; the path will be searched for this program.
ARG_LIST is a NULL-terminated list of character strings to be
passed as the program’s argument list. Returns the process ID of
the spawned process. */
int spawn (char* program, char** arg_list)
{
pid_t child_pid;
/* Duplicate this process. */
child_pid = fork ();
if (child_pid != 0)
/* This is the parent process. */
return child_pid;
else {
/* Now execute PROGRAM, searching for it in the path. */
execvp (program, arg_list);
/* The execvp function returns only if an error occurs. */
fprintf (stderr, “an error occurred in execvp\n”);
abort ();
}
}
int main ()
{
/* The argument list to pass to the “ls” command. */
char* arg_list[] = {
“ls”, /* argv[0], the name of the program. */
“-l”,
“/”,
NULL /* The argument list must end with a NULL. */
};
/* Spawn a child process running the “ls” command. Ignore the
returned child process ID. */
spawn (“ls”, arg_list);
printf (“done with main program\n”);
return 0;
}
[/code:1][/code]

fazi

谢谢各位老兄的回复~~